0144.二叉树的前序遍历
题目大意
输出二叉树的前序遍历
思路与代码
方法一:递归
按照根-左-右顺序递归遍历即可
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var preorderTraversal = function (root) {
const ret = [];
const preorder = (node) => {
if (!node) return null;
ret.push(node.val);
preorder(node.left);
preorder(node.right);
};
preorder(root);
return ret;
};空间复杂度:O(n)
时间复杂度:O(n)
方法二:迭代
借助栈进行迭代
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var preorderTraversal = function (root) {
const ret = [];
const stack = [];
let node = root;
while (node || stack.length > 0) {
while (node) {
ret.push(node.val);
stack.push(node);
node = node.left;
}
node = stack.pop();
node = node.right;
}
return ret;
};空间复杂度:O(n)
时间复杂度:O(n)
