0094. 二叉树的中序遍历
题目链接:https://leetcode.cn/problems/binary-tree-inorder-traversal/description/
题目大意
输出二叉树的中序遍历
思路与代码
方法一:递归
按照左-根-右顺序递归遍历即可
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var inorderTraversal = function (root) {
const ret = [];
const inorder = (node) => {
if (!node) return;
inorder(node.left);
ret.push(node.val);
inorder(node.right);
};
dfs(root);
return ret;
};空间复杂度:O(n)
时间复杂度:O(n)
方法二:迭代
借助栈进行迭代
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var inorderTraversal = function (root) {
const ret = [];
const stack = [];
while (root || stack.length > 0) {
while (root) {
stack.push(root);
root = root.left;
}
root = stack.pop();
ret.push(root.val);
root = root.right;
}
return ret;
};空间复杂度:O(n)
时间复杂度:O(n)
